mavvenegas18 mavvenegas18

23-05-2018
Mathematics

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f(x)= -x-2, g(x)=x^2, what is (g°f)(-6)

Respuesta :

hisroyal1 hisroyal1

23-05-2018

f(x) = -x - 2
g(x) = x^2

(g°f)(-6) = ?

First, we find f(-6)
f(x) = -x - 2
f(-6) = -(-6) - 2
f(-6) = 6 - 2
f(-6) = 4

Since f(-6) = 4,
(g°f)(-6) = g(4)

g(x) = x^2
g(4) = 4^2
g(4) = 16

Therefore, (g°f)(-6) = 16

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