Respuesta :

[tex]\log 600 = \log (100 \cdot 6)= \log 100 + \log 6 = \log 10^2 + \log 6 = \\ 2 \log 10 +\log 6 =2+\log 6 = \boxed{a+2} \\ \hbox{From formulas:} \\ \log a + \log b = \log (ab) \\ \log a^b = b\log a[/tex]