Answer:
[tex]x=4[/tex]
Step-by-step explanation:
start by squaring both sides:
[tex](\sqrt{-8+3x} )^2=(2)^2[/tex]
squaring a square root cancels it out:
[tex]-8+3x = 4[/tex]
solve for x by first adding 8 to both sides:
[tex]3x=12[/tex]
then divide both sides by 3:
[tex]x=4\\[/tex]
