When under a pressure of 9.5 atm, a piston has a volume of 1.7 liters. It the piston is compressed to a
volume of 1.1 liters, what will the new pressure be?
c. 8.90 atm
a. 5.08 atm
b. 6.15 atm
d. 14.7 atm

Respuesta :

Answer:

D

Explanation:

according to boyle's law the temperature and pressure of a gas are inversely proportional given by the equation

p1v1=p2v2

In this case p1 is 9.5,v1 is 1.7,v2 is 1.1 and we have to find p2

9.5Ɨ1.7=p2Ɨ1.1

16.15/11=1.1p2/1.2

p2=14.7

I hope this helps

Answer:

[tex]\boxed {\boxed {\sf D.\ 14.7 \ atm}}[/tex]

Explanation:

We are asked to find the pressure on a gas given a change in volume. We will use Boyle's Law which states the volume of a gas is inversely proportional to the pressure. The formula for this law is:

[tex]P_1V_1=P_2V_2[/tex]

The gas originally has a pressure of 9.5 atmospheres and a volume of 1.7 liters.

[tex]9.5 \ atm * 1.7 \ L = P_2V_2[/tex]

The gas is compressed to a volume of 1.1 liters, but the pressure is unknown.

[tex]9.5 \ atm * 1.7 \ L = P_2* 1.1 \ L[/tex]

We want to find the new pressure, so we must isolate the variable Pā‚‚. It is being multiplied by 1.1 liters. The inverse operation of multiplication is division. Divide both sides of the equation by 1.1 L.

[tex]\frac {9.5 \ atm * 1.7 \ L}{1.1 \ L} =\frac{ P_2* 1.1 \ L}{1.1 \ L}[/tex]

[tex]\frac {9.5 \ atm * 1.7 \ L}{1.1 \ L} =P_2[/tex]

The units of liters cancel.

[tex]\frac {9.5 \ atm * 1.7 }{1.1 } =P_2[/tex]

[tex]\frac {16.15}{1.1} \ atm =P_2[/tex]

[tex]14.6818181818 \ atm= P_2[/tex]

Round to the tenths place. The 8 in the hundredth place tells us to round the 6 up to a 7.

[tex]14.7 \ atm \approx P_2[/tex]

The new pressure at a volume of 1.1 liters is approximately 14.7 atmospheres.