The PQR of the image is a straight line. PQ = QS = QR. Find the magnitude of P^SR in degrees.
Answer:
In ΔPQR, we have
PQ=PR⇒∠R=∠Q
Now, ST∥QR.
⇒∠PST=∠PQR and ∠PTS=∠PRQ [∵ Corresponding angles are equal]
⇒∠PST=∠Q and ∠PTS=∠R
⇒∠PST=∠PTS
⇒PT=PS