Respuesta :

if it has a diameter of 24, then its radius must be half that, or 12.

[tex]\textit{surface area of a sphere}\\\\ SA=4\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12 \end{cases}\implies SA=4\pi (12)^2\implies SA=576\pi[/tex]

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