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PLEASE HELP!!! I'LL GIVE BRAINLIEST AWARD TO ANYONE WHO SHOWS GOOD WORK!!!

Explain how to solve the following system of equation. What is the solution to the system?

2x+2y+z=-5
3x+4y+2z=0
x+3y+2z=1

Respuesta :

Eliminate z from equation 2 and 3: subtract â‘¢ from â‘¡: 2x+y=-1 and call this â‘£.
Double ①: 4x+4y+2z=-10 and call it ⑤.
⑤-②: x=-10.
Substitute x=-10 in â‘£: -20+y=-1, y=19.
Substitute for x and y in â‘ : -20+38+z=-5, z=-23.
Solution: x=-10, y=19, z=-23.

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