A 4800 kg truck is parked on a 12 ∘ slope.how big is the friction force on the truck? the coefficient of static friction between the tires and the road is 0.90.

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26-01-2018
Physics

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A 4800 kg truck is parked on a 12 ∘ slope.how big is the friction force on the truck? the coefficient of static friction between the tires and the road is 0.90.

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satishsolanki1p34q6g satishsolanki1p34q6g · Answer 1 · 2018-01-26T08:20:08+01:00

satishsolanki1p34q6g satishsolanki1p34q6g

26-01-2018

The amount of friction on truck required to stop is = mass*g*sin(12)
= 4800*9.8*sin(12)
= 9780.16 newton

The maximum friction= coefficient of friction* force between tyres and road

Since maximum friction is more than required force to park the truck. Only required amount of friction will act.

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